Read an XML file in AX with namespaces

If you have to read an XML file containing namespaces you have to use the class XmlNamespaceManager.

So, to read this sample XML, that contain 4 namespaces:

<?xml version="1.0" encoding="utf-8"?>
<ns1:Structure xmlns:ns1="http://www.influe.com/xns/2000/xmlfile/deffile/definition" 

               xmlns:gr="http://www.influe.com/xns/2000/xmlfile/deffile/groupe" 

               xmlns:li="http://www.influe.com/xns/2000/xmlfile/deffile/line" 

               xmlns:zn="http://www.influe.com/xns/2000/xmlfile/deffile/zone">
  <gr:MESSAGE>
    <li:TESTATA>
      <zn:TIPO_RECORD_EN>EN</zn:TIPO_RECORD_EN>
      <zn:MITTENTE_MESSAGGIO>4324234</zn:MITTENTE_MESSAGGIO>
 </li:TESTATA>
 <gr:group1>
      <li:GERARCHIA>
  <zn:NUMERO_DESADV_HE>DDT1</zn:NUMERO_DESADV_HE>
   </li:GERARCHIA>
 </gr:group1>
 <gr:group1>
      <li:GERARCHIA>
  <zn:NUMERO_DESADV_HE>DDT2</zn:NUMERO_DESADV_HE>
   </li:GERARCHIA>
 </gr:group1>
 <gr:group1>
      <li:GERARCHIA>
  <zn:NUMERO_DESADV_HE>DDT3</zn:NUMERO_DESADV_HE>
   </li:GERARCHIA>
 </gr:group1> 
  </gr:MESSAGE>
</ns1:Structure>

You can proceed like that:

static void Job92(Args _args)
{
    XmlDocument xmlDoc = XmlDocument::newFile(@"YOURPATH\file.xml");
    XmlNamespaceManager nmgr = new XmlNamespaceManager(new XmlNameTable());
    XmlNode node;
    XmlNodeList nodeList;
    ;
    
    nmgr.addNamespace("ns1", "http://www.influe.com/xns/2000/xmlfile/deffile/definition");
    nmgr.addNamespace("li", "http://www.influe.com/xns/2000/xmlfile/deffile/line");
    nmgr.addNamespace("gr", "http://www.influe.com/xns/2000/xmlfile/deffile/groupe");
    nmgr.addNamespace("zn", "http://www.influe.com/xns/2000/xmlfile/deffile/zone");
    
    // nodo TESTATA
    node = xmldoc.selectSingleNode("//li:TESTATA", nmgr);
    
    infO(node.xml());
    
    // lista group1
    nodeList = xmldoc.selectNodes("//gr:group1");
    
    while(true)
    {
        node = nodeList.nextNode();
        if(node == null)
            break;
            
        // esempio lettura elemento all"interno di group1
        node = node.selectSingleNode("li:GERARCHIA/zn:NUMERO_DESADV_HE", nmgr);
        info(node.text());
    }
}